Prove that : sin(90° - θ)sin θ/tan θ - 1 = -sin^2 θ - Sarthaks

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Prove that : sin(90° - θ)sin θ/tan θ - 1 = -sin2 θ

Maths] If 1 + sin^2θ = 3sinθ cosθ , then prove that tanθ = 1 or 1/2

सिद्ध कीजिये की : (sin (90^@-theta)sin theta)/(tan theta)-1=-sin^2 the

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sin(90-theta)×cos(90-theta)÷tan theta=1-sin^2 theta

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Prove the following: i. tan θ + tan θ = sec θ – sec θ ii. 1/(1−sinθ) + 1/(1 + sinθ) = 2 sec^2θ - Sarthaks eConnect

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