Prove rightarrow sin (90^{o}-theta)cos (90^{o}-theta)=dfrac {tan

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Prove that `(costheta)/sin(90^@+theta)+(sin(-theta))/sin(180^@+theta)-(tan( 90^@+theta))/(cot(th

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dfrac { cos({ 90 }^{ o }-theta )costheta }{ tantheta } +{ cos }^{ 2 }({ 90 }^{ o }-theta )=1

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prove that cot(90-theta) • sin(90-theta)/cos 90-theta) = 1

Simplify:dfrac {sin theta.csc (90-theta).tan theta}{csc (90-theta).cos theta.cot (90-theta)}